solve the equation
15-4x=2(3x+1)
15-4x=6x+1
-4x+6x+1-15
2x-14
x=-14/2=-7
15-4x = 2(3x+1)
15-4x = 6x + 2
Combine all the 'x' terms on one side and the constant terms on the other side.
15 - 2 = 6x + 4x
13 = 10x
So, x=?
No, you made a handfull of errors.
Second line, on the right should be +2
Third line. What happened to equal signs? THis is awfully sloppy work.
15-4x=6x+2
subtract 15 from both sides.
Subtract 6x from both sides.
To solve the equation 15-4x=2(3x+1), let's go step by step.
Step 1: Distribute the 2 on the right side of the equation.
We have 15-4x=6x+2.
Step 2: Move all the terms with x to one side and the constant terms to the other side.
To do this, let's subtract 6x from both sides. This gives us:
15-4x-6x = 6x-6x+2.
Simplifying the left side further, we get:
15-10x = 2.
Step 3: Move the constant term to the other side.
To get rid of the 15 on the left side, we subtract 15 from both sides:
15-10x-15 = 2-15.
Simplifying, we get:
-10x = -13.
Step 4: Solve for x.
To isolate x, we can divide both sides of the equation by -10:
-10x/-10 = -13/-10.
Simplifying, we have:
x = 13/10 or x = 1.3.
So, the solution to the equation 15-4x=2(3x+1) is x = 13/10 or x = 1.3.