Solve this service problem.
Number of dinners = 115
Individual portion = 6 oz.
Size of can = 32 oz.
Number of cans required
(115 * 6) / 32 =
To solve this problem, we can use the following steps:
Step 1: Determine the total amount of dinner required.
To find the total amount of dinner required, we multiply the number of dinners by the individual portion size.
Total amount of dinner = number of dinners * individual portion size
Total amount of dinner = 115 * 6 oz.
Step 2: Determine the number of cans required.
To find the number of cans required, we divide the total amount of dinner by the size of each can.
Number of cans required = total amount of dinner / size of can
Number of cans required = (115 * 6 oz.) / 32 oz.
Let's calculate the number of cans required:
Total amount of dinner = 115 * 6 = 690 oz.
Number of cans required = 690 oz. / 32 oz.
Using division, we find that the number of cans required is approximately 21.5625 cans.
Therefore, the number of cans required for 115 dinners, assuming an individual portion size of 6 oz. and a can size of 32 oz., is approximately 21.5625 cans.
To solve this service problem, we need to determine the number of cans required to serve 115 dinners.
First, we need to figure out how many ounces of food are needed in total for 115 dinners. To do this, we multiply the number of dinners by the individual portion size:
Total ounces of food = Number of dinners * Individual portion size
Total ounces of food = 115 * 6 oz
Total ounces of food = 690 oz
Next, we need to calculate how many cans of food are required when each can contains 32 ounces. To do this, we divide the total ounces of food by the size of one can:
Number of cans required = Total ounces of food / Size of one can
Number of cans required = 690 oz / 32 oz (approximated as 21.563)
To obtain the whole number of cans required, we round up to the nearest whole number. In this case, we need to round up because we cannot have a fraction of a can.
Number of cans required = Round up(Number of cans required)
Number of cans required = Round up(21.563) = 22
Therefore, to serve 115 dinners with each dinner portioned at 6 oz and using cans with a size of 32 oz, you would need a total of 22 cans.