Calculus Help and Check

find the derivative of the function

integral from cosx to sinx (ln(8+3v)dv)

y'(x)= (sin(8+3((sin(x)))+x)+sin(8+3sin(x)-x))/2

Is this the right answer?????

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asked by Chris
  1. I gave you my answer which is quite different.

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    posted by Damon
  2. Hmm. I thought that, using Leibniz' Rule,

    F'(x) = ln(8+3sinx)*cosx - ln(8+3cosx)(-sinx)

    Did I miss something there?

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    posted by Steve

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