Calculate the pH of the resulting solution if 25.0 mL of 0.250 M HCl(aq) is added to
(a) 35.0 mL of 0.250 M NaOH(aq).
(b) 15.0 mL of 0.350 M NaOH(aq).

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  1. Some one please help

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  2. I found the answer to a however i keep doing something wrong for b

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  3. My guess is that you didn't take into account the total volume.

    millimols HCl=mL x M = 25 x 0.250 = 6.25
    mmols NaOH = 15 x 0.35 = 5.25
    NaOH + HCl ==> H2O + NaCl

    mmols HCl = 6.25
    mmols NaoH = 5.25
    difference is excess HCl by 1.00 mmol.
    So you have 1.00 mmols HCl in a total volume of 40 mL.
    M HCl = mmols/mL = ? and convert H^+ to pH.
    Post your work if you still don't get the right answer.

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