The spinner is spun twice. What is the probability it will stop on either 3 or 5 the first time and will stop on 2 the second time?
The spinner has number 1 through 8. And is spun twice. What is the probability it will stop on either 3 or 5 the first time and will stop on 2 the second time?
prob(3 or 5) = 2/8 = 1/4
prob(2) = 1/8
prob(3or5 then 2) = (1/4)(1/8) = 1/32
Thanks for answering
the spinner is 1 and 6
To find the probability of the spinner stopping on either 3 or 5 on the first spin and then stopping on 2 on the second spin, we need to consider the total number of outcomes and the number of favorable outcomes.
Let's break it down step by step:
Step 1: Determine the total number of outcomes
Assuming the spinner has equally likely outcomes, let's say it has 6 numbers (1, 2, 3, 4, 5, and 6). Therefore, there are 6 possible outcomes on the first spin and 6 possible outcomes on the second spin.
Total number of outcomes = 6 (for the first spin) * 6 (for the second spin) = 36
Step 2: Determine the number of favorable outcomes
We want the spinner to stop on either 3 or 5 on the first spin and then stop on 2 on the second spin.
On the first spin, there are 2 favorable outcomes (3 or 5). On the second spin, there is 1 favorable outcome (2).
Number of favorable outcomes = 2 (for the first spin) * 1 (for the second spin) = 2
Step 3: Calculate the probability
To find the probability, we divide the number of favorable outcomes by the total number of outcomes.
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 2 / 36 = 1 / 18 ≈ 0.0556
So, the probability that the spinner will stop on either 3 or 5 on the first spin and then stop on 2 on the second spin is approximately 0.0556 or 5.56%.
not enough information, what kind of spinner?
how many positions are possible ?