Algebra 2

log base 3of 6 + log base3 (3x + 1) = 2

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  1. since loga + logb = log ab, we have

    log3 6(3x+1) = 2
    6(3x+1) = 9
    18x = 3
    x = 1/6

    so, how come, when I worked this out for you, assuming base 10, you didn't just follow the same steps, with a change of base?

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