A stone is thrown in vertical upward direction with velocity of 5 m/s. if the acceleration of the stone during it motion is 10 m/s2 in h downward direction, what will be the height attained by the stone and how much time will it take to reach there?
V = Vo + a*Tr = 0 @ max. ht.
Tr = -Vo/a = -5/-10 = 0.5 s. = Rise time
or time to reach max. ht.
h = Vo*t + 0.5a*Tr^2 = 5*0.5 - 5*0.5^2 = 1.25 m.