A cylinder with a movable piston has the square meter 24cm2. How far will the piston go down if 5.0 kg weight is laid on the piston and the temperature remains the same?
P: 1.0 atm.
Help please :)
I do not know V, the initial Volume of gas so can not do the problemP V = n R T
P dV + V dP = 0 if n R and T do not change
P initial = 10^5 Newtons/m^2 ( or Pacals)
dV = (24*10^-4) x
V = I have no idea. You left this out.
dP = 5*9.81/(24*10^-4)
posted by Damon