How do i balance Cu(NO3)2 + HNO3
Easy. There is no reaction. Are you sure you don't have this confused with Cu + HNO3?
To balance the chemical equation Cu(NO3)2 + HNO3, also known as the reaction between copper(II) nitrate and nitric acid, you need to follow these steps:
Step 1: Write down the unbalanced chemical equation.
Cu(NO3)2 + HNO3 → Cu(NO3)2 + NO + H2O
Step 2: Count the number of atoms of each element on both sides of the equation. In this case, there are:
Copper (Cu): 1 atom on both sides
Nitrogen (N): 2 atoms on the left, 1 atom on the right
Oxygen (O): 10 atoms on the left, 6 atoms on the right
Hydrogen (H): 1 atom on the right
Step 3: Start balancing the elements that appear in the most complex compounds first. In this case, we'll start with nitrogen (N) and oxygen (O).
Step 4: Balance the number of nitrogen atoms by adding a coefficient in front of HNO3. The coefficient should be the same as the number of nitrate ions (NO3-) in copper(II) nitrate (Cu(NO3)2), which is 2.
Cu(NO3)2 + 2HNO3 → Cu(NO3)2 + NO + H2O
Step 5: Now, balance the oxygen atoms by adjusting the coefficients in front of HNO3 and H2O. Since there are already 6 oxygen atoms on the right, we need another 4 oxygen atoms on the left. This can be achieved by adding a coefficient of 2 in front of Cu(NO3)2.
2Cu(NO3)2 + 2HNO3 → 2Cu(NO3)2 + NO + H2O
Step 6: Finally, check if all the elements are balanced. In this case, we have:
Copper (Cu): 2 atoms on both sides
Nitrogen (N): 2 atoms on both sides
Oxygen (O): 12 atoms on both sides
Hydrogen (H): 2 atoms on both sides
Now the equation is balanced:
2Cu(NO3)2 + 2HNO3 → 2Cu(NO3)2 + NO + H2O