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How many grams of CuSO4 * 5H2O are needed to prepare 100.ml of a 0.10 M solution?
How many mols do you want? That's M x L = mols
Then mols = grams/molar mass. You know mols and molar mass, solve for grams.
To calculate the amount of CuSO4 * 5H2O needed to prepare a 0.10 M solution, you'll need to follow these steps:
Step 1: Determine the molar mass of CuSO4 * 5H2O
The molar mass of CuSO4 * 5H2O can be calculated by adding up the atomic masses of all the elements in the compound.
- Copper (Cu): 63.55 g/mol
- Sulphur (S): 32.07 g/mol
- Oxygen (O): 16.00 g/mol
- Hydrogen (H): 1.01 g/mol
- Water (H2O): (2 * 1.01 g/mol) + 16.00 g/mol = 18.02 g/mol
Now, calculate the molar mass of CuSO4 * 5H2O:
(63.55 g/mol) + (32.07 g/mol) + (4 * 16.00 g/mol) + (5 * 18.02 g/mol) = 249.68 g/mol
Step 2: Calculate the number of moles needed
The molarity (M) is defined as moles of solute per liter of solution. In this case, you need 0.10 moles of CuSO4 * 5H2O in 1 liter of solution (1000 ml).
To calculate the number of moles needed for 100 ml (0.1 liters) of solution, use the formula:
moles = Molarity * Volume (in liters)
moles = 0.10 mol/L * 0.1 L = 0.01 moles
Step 3: Calculate the mass required
To find the mass required, use the equation:
mass = moles * molar mass
mass = 0.01 moles * 249.68 g/mol = 2.50 grams
Therefore, you would need 2.50 grams of CuSO4 * 5H2O to prepare 100 ml of a 0.10 M solution.
To calculate how many grams of CuSO4 * 5H2O are needed to prepare a 0.10 M solution, you will need to use the molar mass and the formula of the compound. Here's how you can do it:
Step 1: Determine the molar mass of CuSO4 * 5H2O.
To do this, you need to calculate the individual molar masses of each element in the compound and sum them up. The molar masses of Cu, S, O, and H are available in the periodic table.
- Mass of CuSO4 = molar mass of Cu + molar mass of S + (4 * molar mass of O)
- Mass of H2O = (2 * molar mass of H) + (1 * molar mass of O)
- Total molar mass of CuSO4 * 5H2O = Mass of CuSO4 + (5 * Mass of H2O)
Step 2: Calculate the number of moles needed.
The molarity (M) is defined as the number of moles of solute divided by the volume of the solution in liters.
- Moles of CuSO4 * 5H2O = Molarity * Volume (in liters)
To use this equation, you need to convert the given volume of the solution from milliliters to liters.
Step 3: Convert moles to grams.
Now that you have the number of moles of CuSO4 * 5H2O, you can use it to calculate the mass of the compound using its molar mass.
- Mass (in grams) = Moles * Molar mass
Here's an example calculation:
Given:
- Volume of the solution = 100 mL = 0.1 L
- Molarity = 0.10 M
Step 1:
- Molar mass of CuSO4 = 63.55 g/mol
- Molar mass of H2O = 18.02 g/mol
- Total molar mass of CuSO4 * 5H2O = (63.55 g/mol) + (5 * 18.02 g/mol) = 249.57 g/mol
Step 2:
- Moles of CuSO4 * 5H2O = (0.10 M) * (0.1 L) = 0.01 moles
Step 3:
- Mass (in grams) = (0.01 moles) * (249.57 g/mol) = 2.5 grams
Therefore, you will need 2.5 grams of CuSO4 * 5H2O to prepare 100 mL of a 0.10 M solution.