did i use the chain rule correctly? y=(8x^4-5x^2+1)^4 d(f(x)/dx =d/dx ((8x^4-5x^2+1)^4) =4*(8x^4-5x^2+1)^3*d/dx(8x^4-5x^2+1) =4*(8*d/dx(x^4)-5*d/dx(x^2))*(8x^4-5x^2+1)^3 =4*(8*4x^3-5*2x)*(8x^4-5x^2+1)^3
i need to find the derivative using chain rule: (x^2 + 2x - 6)^2 (1-x^3)^2 i got the answer from a site but the problem is i cannot get my work to match up with the answer, i don't know what im doing wrong. answer: 10x^9 + 36x^8
Find the equation of the tangent line 5x^2+y^2=14 at (1,3). P.S: It's calculus. So far I know this much 10x+2y(dy/dx)=o -10x -10x ___________________ 2y(dy/dx)= -10x (dy/dx)= -10x/2y= -5x/y m= -5(1)/3= -5/3 y=mx+b 3= -5/3(1)+b
can anyone help with this? suppose you bought some 32 cents stamps and some 20 cents stamps. you spent $3.92 for 16 stamps. how many of each stamp did you buy? i got the equation--.32x + .20y = $3.92 but don't know how to solve
An open box is to be made from a square piece of cardboard, 32 inches on a side, by cutting equal squares with sides of length x from the corners and turning up the sides (see figure below). Determine the function, V, in terms of
5.Simplify x/6x-x^2 a)1/6-x ; where x=0.6 b) 1/6-x; where x=6*** c)1/6x; where x=0 d)1/6 6. 5x^3/7x^3+x^4 a)5/7+x; where x= 0,-7**** b)5/7+x; where x=-7 c)5/7x; where x=0 d)5/7 7.x-2/x^2+4x-12 a)1/6+x; where x=-6*** b)1/6+x; where
The volume of the box is represented by (x^2+5x+6)(x+5). Find the polynomial that represents the area of the bottom of the box. can some explain how to get the solution Divide the volume by the height to get the area of the
To construct a tincan, V=32pi m^3, The cost per square meter of the side is half of the top and bottom of can. What are the dimensions and the cost? V=πr²h=32pi SA=2πr²+2πrh h=32/r² Domain={r>o} Let x be the
1. (-10x^3 + 30x -20) divided by (-5x+5)? a)2x^2-2x+4**** b)-2x^2-2x-4 c)-2x^2+2x+4 d)2x^2+2x-4 2.The width, w, of a rectangular playground is x + 3. The area of the garden is x^3 - 7x + 6. What is an expression for the length of