A system which undergoes an adiabatic change (i.e., q = 0) and has work done on it by the surroundings has

a. w < 0, ΔU = 0
b. w < 0, ΔU < 0
c. w > 0, ΔU < 0
d. w > 0, ΔU > 0
e. w < 0, ΔU > 0

dE = q+w.

If q = 0, then
dE = w
If work is done on it by the surroundings then w is + and that makes dE +. Wouldn't that be d?

In an adiabatic change, q = 0, which means that no heat is exchanged between the system and its surroundings. If work is done on the system by the surroundings, it implies that work is being done on the system and the energy of the system is increasing.

Therefore, the correct option is:

d. w > 0, ΔU > 0

To determine the answer to this question, we need to understand the relationship between work (w), internal energy change (ΔU), and heat (q) in an adiabatic process.

In an adiabatic process, no heat is transferred between the system and the surroundings (q = 0). Therefore, the only form of energy transfer is through work.

When work is done on a system by the surroundings (w > 0), the system gains energy. As a result, the internal energy of the system increases (ΔU > 0).

Conversely, when work is done by the system on the surroundings (w < 0), the system loses energy. In this case, the internal energy of the system decreases (ΔU < 0).

From the information given in the question (q = 0) and work done on the system by the surroundings, we can conclude that the answer is:

e. w < 0, ΔU > 0

Explanation:

- Work done on the system by the surroundings (w < 0)
- Internal energy change is positive (ΔU > 0) since energy is added to the system.

Therefore, the correct option is e. w < 0, ΔU > 0.