Shorten fraction:
(x^2+2x)/(4x+8)= ?
and
reduce:
(8a^3*b*a^-2)/(2b)^2= ?
First. In the numerator, factor out an x. In the denominator, factor out a 4. this will leave a common factor that can be divided out.
Second.change the numerator to 8ab. Check that to see if it is right.
change the denominator to 4b^2
now you have 8ab/4b^2 reduce the 8/4, and the b/ b^2
1) ánswer X/8
2) answer:2ab
or wrong?
To shorten the fraction (x^2+2x)/(4x+8), we can factor out an x from the numerator and factor out a 4 from the denominator.
(x^2+2x)/(4x+8) becomes x(x+2)/4(x+2).
Notice that (x+2) appears in both the numerator and denominator. We can cancel out this common factor, leaving us with x/4 as the simplified fraction.
So the answer to the first question is x/4.
Now let's move on to the second question. The fraction is (8a^3*b*a^-2)/(2b)^2.
In the numerator, we can simplify by combining the exponents and get 8a^(3-2)*b, which becomes 8ab.
In the denominator, (2b)^2 means (2b)*(2b), which gives us 4b^2.
So the fraction reduces to 8ab/4b^2.
We can simplify further by dividing both the numerator and denominator by their common factor, 4.
8ab/4b^2 becomes 2ab/b^2.
Therefore, the answer to the second question is 2ab/b^2.
In summary, the two answers are x/4 for the first question and 2ab/b^2 for the second question.