Compute the following values for the given function.
h(x,y)=(2x+8y)/(x-y)
a. h(0,1)= ?
b. h(-1,1)= ?
c. h(2,1)= ?
d. h(pi,-pi)= ?
Just drop in the values and stir.
e.g.
c) x = 2, y=1
h(2,1) = (4+8)/(2-1) = 12
That's all there is to it.
ok thanks it is pretty easy.
To compute the values for the given function, h(x,y)=(2x+8y)/(x-y), we substitute the given values into the function and simplify the expression.
a. To find h(0,1), substitute x=0 and y=1 into the function:
h(0,1) = (2(0) + 8(1))/(0-1)
= (0 + 8)/(-1)
= 8/(-1)
= -8
b. To find h(-1,1), substitute x=-1 and y=1 into the function:
h(-1,1) = (2(-1) + 8(1))/(-1-1)
= (-2 + 8)/(-2)
= 6/(-2)
= -3
c. To find h(2,1), substitute x=2 and y=1 into the function:
h(2,1) = (2(2) + 8(1))/(2-1)
= (4 + 8)/(1)
= 12/1
= 12
d. To find h(pi,-pi), substitute x=pi and y=-pi into the function:
h(pi,-pi) = (2(pi) + 8(-pi))/(pi-(-pi))
= (2pi - 8pi)/(pi + pi)
= (-6pi)/(2pi)
= -3/1
= -3
Therefore, the values for the given function are:
a. h(0,1) = -8
b. h(-1,1) = -3
c. h(2,1) = 12
d. h(pi,-pi) = -3