The potential energy of a +2 x 10-6 C charge decreases from 0.15 J to 0.05 J when it is moved from point A to point B. What is the change in electric potential between these two points? Do not enter any (-) sign in your answer.
Hey, this is the first problem I did for you backwards.
same thing again and again
Volts is potential energy PER UNIT charge
That is why they call Volts electric potential
change in potential energy = charge * volts !!!
0.15j-0.05j=0.1
0.1=__*2x10^-6c
0.1/2x10^-6c=___
50000=__
so answer 50000j/c?
.1 Joules = 2*10^-6 V
V = .1 * 10^6 /2 = .05*10^6 = 5*10^4
= 50,000 volts
Yes :)
and yes, volts is Joules per coulomb
To find the change in electric potential between two points, we can use the formula:
ΔV = Vfinal - Vinitial
In this case, the initial potential energy is 0.15 J and the final potential energy is 0.05 J. However, potential energy is measured in joules (J), while electric potential is measured in volts (V). To convert from potential energy to electric potential, we need to divide the potential energy by the charge's magnitude.
Given:
Initial potential energy, Vinitial = 0.15 J
Final potential energy, Vfinal = 0.05 J
Charge, q = +2 x 10^(-6) C
Let's calculate the change in electric potential step by step:
Step 1: Convert potential energy to electric potential
Let's convert the initial and final potential energy to electric potential:
Vinitial = Vinitial / q
= 0.15 J / (+2 x 10^(-6) C)
= 75,000 V
Vfinal = Vfinal / q
= 0.05 J / (+2 x 10^(-6) C)
= 25,000 V
Step 2: Calculate the change in electric potential
Now that we have the initial and final electric potential, we can find the change in electric potential:
ΔV = Vfinal - Vinitial
= 25,000 V - 75,000 V
= -50,000 V
Note that we do not include any negative sign in our answer, as the question explicitly states not to include it. Therefore, the change in electric potential between points A and B is 50,000 volts (V).