# physics

A charge of +0.5 C is moved from a position where the electric potential is 10 V to a position where the electric potential is 70 V. What is the the change in potential energy of the charge associated with this change in position?

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1. I am going to scream!
Voltage = change in potential per unit charge.
change in potential energy = q * change in V

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2. so ...
change in PE=.5 times 10v?

sorry my professor didn't cover what C or V equations are

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3. how do you figure out change in V?
is it 10v- 70v? then times it by .5c and get the change in PE??

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4. Yes, 90 volts * .5 coulombs = change in potential energy

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5. 45J, correct?

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6. Yes, 60 volts * .5 coulombs = change in potential energy

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7. That is 30 Joules

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8. 30J*?

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9. thank you. my professor gave us a change in GPE=mgh and a E=Fe/q equations and was confused

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10. Yes, m g h is joules in gravitational acceleration g

E q = Force (Newtons)
so
E q d = work (Joules) = increase in potential energy
so
E d = increase in potential energy per unit charge which we call V, voltage or electric potential (per Coulomb implied).

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11. E q = Force (Newtons) { like m g )
so
E q d = work (Joules) = increase in potential energy (like m g h)
so
E d = increase in potential energy per unit charge which we call V, voltage or electric potential (per Coulomb implied).
like g h (increase in potential energy per unit mass)

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