physics

A charge of +0.5 C is moved from a position where the electric potential is 10 V to a position where the electric potential is 70 V. What is the the change in potential energy of the charge associated with this change in position?

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  1. I am going to scream!
    Voltage = change in potential per unit charge.
    change in potential energy = q * change in V

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  2. so ...
    change in PE=.5 times 10v?

    sorry my professor didn't cover what C or V equations are

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  3. how do you figure out change in V?
    is it 10v- 70v? then times it by .5c and get the change in PE??

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  4. Yes, 90 volts * .5 coulombs = change in potential energy

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  5. 45J, correct?

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  6. Yes, 60 volts * .5 coulombs = change in potential energy

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  7. That is 30 Joules

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  8. 30J*?

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  9. thank you. my professor gave us a change in GPE=mgh and a E=Fe/q equations and was confused

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  10. Yes, m g h is joules in gravitational acceleration g

    E q = Force (Newtons)
    so
    E q d = work (Joules) = increase in potential energy
    so
    E d = increase in potential energy per unit charge which we call V, voltage or electric potential (per Coulomb implied).

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  11. E q = Force (Newtons) { like m g )
    so
    E q d = work (Joules) = increase in potential energy (like m g h)
    so
    E d = increase in potential energy per unit charge which we call V, voltage or electric potential (per Coulomb implied).
    like g h (increase in potential energy per unit mass)

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