Identify any real and extraneous solutions for the equations below.
Sqrt p = -1
√-1 = i
https://www.google.com/search?client=safari&rls=en&q=square+root+of+negative+one&ie=UTF-8&oe=UTF-8
To identify any real and extraneous solutions for the equation sqrt(p) = -1, we need to solve for the variable p.
Taking the square of both sides of the equation, we get:
(sqrt(p))^2 = (-1)^2
p = 1
Now we have obtained p = 1 as the solution to the equation. However, we need to check if this solution is valid or if it is an extraneous solution.
To do this, we need to verify if p = 1 satisfies the original equation sqrt(p) = -1.
Taking the square root of both sides of the equation p = 1, we find:
sqrt(p) = sqrt(1)
sqrt(p) = 1
Now, we compare this result with the right-hand side of the original equation, which requires sqrt(p) to be equal to -1. Since sqrt(p) = 1 ≠ -1, we can conclude that p = 1 is not a valid solution to the equation sqrt(p) = -1.
Therefore, there are no real solutions for the equation sqrt(p) = -1.