Hello.I need to rearrange the following to make b the subject'
a = 10/b-z. Im getting confused with how to rearrange when theres division involved.
If a=c/(b-d)
to get d to the numerator, multiply both sides by (b-d)
a(b-d)=c (b-d)/(b-d)
=c
divide both sides by a..
b-d=c/a
I assume you can use this example.
To rearrange the equation and make 'b' the subject, follow these steps:
Step 1: Start by isolating the term involving 'b' on one side of the equation. In this case, you want to move the 'z' term to the other side.
a = 10/b - z
Adding 'z' to both sides of the equation:
a + z = 10/b
Step 2: Now, you want to eliminate the fraction by getting rid of the denominator on the right side. To do that, multiply both sides of the equation by 'b':
b(a + z) = 10/b * b
This simplifies to:
b(a + z) = 10
Step 3: Distribute 'b' to both terms (a and z) on the left side of the equation:
ba + bz = 10
Step 4: Finally, rearrange the equation to make 'b' the subject by subtracting 'ba' from both sides:
bz = 10 - ba
Divide both sides by 'z' to isolate 'b':
b = (10 - ba)/z
Therefore, the rearranged equation with 'b' as the subject is:
b = (10 - ba)/z