Erica painted a picture of her dog. The picture has an area of 3600 cm square and is square. She has placed the picture in a frame that is 5 cm wide. What is the perimeter of the picture frame?

If the picture is square then it must be sqr6 3600 = 60 cm each edge.

If the picture frame is 5cm wide, and assuming no overlap between the picture and the frame, the total length of frame + picture is 60 + left side frame + right side frame = 70 cm.
The perimeter is the distance around so that is 4*70 cm = ?

To find the perimeter of the picture frame, we need to determine the dimensions of the picture and the frame. Let's calculate step by step:

1. Calculate the side length of the picture:
Since the picture is square, the area can be calculated by finding the square of the side length.

Let's denote the side length of the picture as "x".

Given that the area of the picture is 3600 cm², we have the equation:
x² = 3600

To find the value of x, we take the square root of both sides:
√(x²) = √3600
x = 60 cm

So the side length of the picture is 60 cm.

2. Calculate the dimensions of the framed picture:
The picture frame is 5 cm wide on all sides, which means the dimensions of the framed picture will be 5 cm longer and wider than the dimensions of the picture.

The length and width of the framed picture would be:
Length = x + 2 * frame width = 60 + 2 * 5 = 70 cm
Width = x + 2 * frame width = 60 + 2 * 5 = 70 cm

3. Calculate the perimeter of the framed picture:
The perimeter of any shape is the sum of all its sides.

For the framed picture, we have two sides measuring 70 cm and two sides measuring 60 cm.

Therefore, the perimeter of the framed picture is:
Perimeter = 2 * (Length + Width) = 2 * (70 + 60) = 2 * 130 = 260 cm

So, the perimeter of the picture frame is 260 cm.