One mole of pentanol (C5H11OH) contains how many hydrogen (H) atoms?
1 mol C5H11OH contains 12 mol H atoms. Each mol contains 6.02E23 individual atoms so 12 mols will contain ....... atoms.
To determine the number of hydrogen (H) atoms in one mole of pentanol (C5H11OH), we need to count the number of hydrogen atoms present in the chemical formula.
The formula of pentanol, C5H11OH, indicates that there are 11 hydrogen atoms in each molecule.
Since one mole represents Avogadro's number (6.022 x 10^23) of particles, we can say that one mole of pentanol contains 11 x (6.022 x 10^23) hydrogen atoms.
Therefore, one mole of pentanol contains 6.6242 x 10^24 hydrogen atoms.
To determine the number of hydrogen (H) atoms in one mole of pentanol (C5H11OH), we need to examine the chemical formula and count the number of hydrogen atoms.
The general rule is that subscripts in a chemical formula indicate the number of atoms present. In this case, the subscript 5 after the C indicates that there are five carbon (C) atoms in a molecule of pentanol. The subscript 11 after the H indicates that there are eleven hydrogen (H) atoms in a molecule of pentanol.
Since one mole of any substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23, we can conclude that there are 11 x 6.022 x 10^23 hydrogen atoms in one mole of pentanol.
Therefore, one mole of pentanol contains approximately 6.6242 x 10^24 hydrogen (H) atoms.