what is the balanced equation for ozone gas reacts with 2,3,4,5-tetramethylheptane, CH3-CH(CH3)-CH(CH3)-CH(CH3)-CH(CH3)-CH2-CH3 , to produce carbon dioxide gas, CO2 , and water vapor, H2O

To determine the balanced equation for the reaction between ozone gas (O3) and 2,3,4,5-tetramethylheptane (C8H18), we first need to identify the molecular formulas of the products formed: carbon dioxide (CO2) and water vapor (H2O).

Let's start by writing the unbalanced equation for the reaction:
O3 + C8H18 → CO2 + H2O

Next, we need to balance the number of atoms on both sides of the equation. To achieve this, we can follow a step-by-step approach:

Step 1: Count the number of each type of atom on both sides of the equation.
On the left-hand side (reactants):
Oxygen (O): 3
Hydrogen (H): 18
Carbon (C): 8

On the right-hand side (products):
Oxygen (O): 2 (from CO2) + 1 (from H2O) = 3
Hydrogen (H): 2 (from H2O)
Carbon (C): 1 (from CO2)

Step 2: Balance the number of carbon atoms by modifying the coefficient in front of CO2 on the right-hand side (products).
Since there are 8 carbon atoms in the reactant, we assign the coefficient 8 to CO2:
O3 + C8H18 → 8CO2 + H2O

Step 3: Balance the number of hydrogen atoms by adjusting the coefficient in front of H2O:
Since there are 18 hydrogen atoms in the reactant and each H2O produces 2 hydrogen atoms, we assign the coefficient 9 to H2O:
O3 + C8H18 → 8CO2 + 9H2O

Step 4: Balance oxygen atoms by adjusting the coefficient in front of O3:
Since there are three oxygen atoms in each O3 molecule and we have 8 CO2 molecules, we will need 24 oxygen atoms in total. To equalize the number of oxygen atoms on both sides of the equation, we assign the coefficient 8 to O3:
8O3 + C8H18 → 8CO2 + 9H2O

Thus, the balanced equation for the reaction between ozone gas and 2,3,4,5-tetramethylheptane will be:
8O3 + C8H18 → 8CO2 + 9H2O

To find the balanced equation for the reaction between ozone gas (O3) and 2,3,4,5-tetramethylheptane (CH3-CH(CH3)-CH(CH3)-CH(CH3)-CH(CH3)-CH2-CH3) to produce carbon dioxide gas (CO2) and water vapor (H2O), we need to determine the chemical formulas and balance the equation.

First, let's write out the reaction:

Ozone gas (O3) + 2,3,4,5-tetramethylheptane (CH3-CH(CH3)-CH(CH3)-CH(CH3)-CH(CH3)-CH2-CH3) → Carbon dioxide gas (CO2) + Water vapor (H2O)

Now, let's determine the chemical formulas for the compounds involved:

Ozone gas: O3
2,3,4,5-tetramethylheptane: CH3-CH(CH3)-CH(CH3)-CH(CH3)-CH(CH3)-CH2-CH3
Carbon dioxide gas: CO2
Water vapor: H2O

Next, we need to balance the equation by ensuring that the number of atoms of each element is the same on both sides of the equation.

Let's start by balancing the carbon (C) atoms:

On the reactant side: 1 C atom (from 2,3,4,5-tetramethylheptane)
On the product side: 1 C atom (from carbon dioxide gas)

So, the carbon (C) atoms are already balanced.

Now let's balance the hydrogen (H) atoms:

On the reactant side: 14 H atoms (from 2,3,4,5-tetramethylheptane)
On the product side: 2 H atoms (from water vapor)

We can balance the hydrogen atoms by multiplying the reactant side by 7:

7(Ozone gas) + 2,3,4,5-tetramethylheptane → 2(Carbon dioxide gas) + 7(Water vapor)

Now, let's balance the oxygen (O) atoms:

On the reactant side: 9 O atoms (from ozone gas)
On the product side: 4 O atoms (from carbon dioxide gas) + 7 O atoms (from water vapor)

To balance the oxygen atoms, we can multiply ozone gas by 4 and water vapor by 9:

4(Ozone gas) + 2,3,4,5-tetramethylheptane → 4(Carbon dioxide gas) + 9(Water vapor)

Therefore, the balanced equation for the reaction is:

4 Ozone gas + 2,3,4,5-tetramethylheptane → 4 Carbon dioxide gas + 9 Water vapor