Given the following reaction:
CaC2 + 2 H2O C2H2 + Ca(OH)2
How many moles of Ca(OH)2 will be produced if 5.800 g of CaC2 are reacted completely?
To find the number of moles of Ca(OH)2 produced when 5.800 g of CaC2 is reacted completely, we first need to calculate the number of moles of CaC2 used.
Step 1: Calculate the molar mass of CaC2.
The molar mass of Ca is 40.08 g/mol.
The molar mass of C is 12.01 g/mol.
The molar mass of CaC2 is (40.08 g/mol) + 2 * (12.01 g/mol) = 64.10 g/mol.
Step 2: Calculate the number of moles of CaC2.
The number of moles of CaC2 is given by:
moles = mass / molar mass
moles = 5.800 g / 64.10 g/mol ≈ 0.090 moles.
Step 3: Determine the stoichiometry of the reaction.
From the balanced reaction, we see that 1 mole of CaC2 produces 1 mole of Ca(OH)2.
Therefore, the number of moles of Ca(OH)2 produced is also 0.090 moles.
So, 0.090 moles of Ca(OH)2 will be produced if 5.800 g of CaC2 are reacted completely.
To determine the number of moles of Ca(OH)2 produced when 5.800 g of CaC2 is reacted completely, we need to first calculate the number of moles of CaC2.
The molar mass of CaC2 is the sum of the atomic masses of calcium (Ca) and carbon (C), multiplied by the number of atoms present in each element in the compound. Looking up the atomic masses on the periodic table:
Ca: 40.08 g/mol
C: 12.01 g/mol
The molar mass of CaC2 is calculated as follows:
(1 * 40.08 g/mol) + (2 * 12.01 g/mol) = 64.10 g/mol
Next, we can calculate the number of moles of CaC2 using the given mass and the molar mass.
Number of moles = mass / molar mass
Number of moles = 5.800 g / 64.10 g/mol
Number of moles ≈ 0.0905 mol (rounded to four decimal places)
From the balanced equation, we can see that the ratio of moles of CaC2 to moles of Ca(OH)2 is 1:1. Therefore, the number of moles of Ca(OH)2 produced will also be approximately 0.0905 mol.
So, 0.0905 moles of Ca(OH)2 will be produced when 5.800 g of CaC2 is reacted completely.