What is the net ionic equations for:
1. Arsenic(III) iodide + Sodium sulfide
2. Lead(II) nitrate + Ammonium oxalate
3. Magnesium chromate + Copper(II) sulfate
Pb^2+ + C2O4^2- ==> PbC2O4
CrO4^2- + Cu^2+ ==> CuCrO4
As^3+ + S^2- ==> As2S3 you balanced
To determine the net ionic equations for these reactions, we need to first write out the balanced molecular equations, followed by the ionic equations, and finally determine the net ionic equations by canceling out spectator ions.
1. Arsenic(III) iodide + Sodium sulfide
The balanced molecular equation is:
AsI3 + 3Na2S → As2S3 + 6NaI
To write the ionic equation, we break apart the soluble ionic compounds into their respective ions:
AsI3(s) + 3Na2S(aq) → As2S3(s) + 6NaI(aq)
Next, we separate the strong electrolytes into ions:
As3+(aq) + 3I^-(aq) + 6Na+(aq) + 3S^2-(aq) → As2S3(s) + 6Na+(aq) + 6I^-(aq)
Finally, we cancel out the spectator ions, which are the ions that appear on both sides of the equation:
As3+(aq) + 3I^-(aq) + 3S^2-(aq) → As2S3(s)
The net ionic equation is:
As3+(aq) + 3I^-(aq) + 3S^2-(aq) → As2S3(s)
2. Lead(II) nitrate + Ammonium oxalate
The balanced molecular equation is:
Pb(NO3)2 + (NH4)2C2O4 → PbC2O4 + 2NH4NO3
To write the ionic equation, we break apart the soluble ionic compounds into their respective ions:
Pb(NO3)2(aq) + (NH4)2C2O4(aq) → PbC2O4(s) + 2NH4NO3(aq)
Next, we separate the strong electrolytes into ions:
Pb2+(aq) + 2NO3^-(aq) + 2NH4+(aq) + C2O4^2-(aq) → PbC2O4(s) + 2NH4+(aq) + 2NO3^-(aq)
Finally, we cancel out the spectator ions:
Pb2+(aq) + C2O4^2-(aq) → PbC2O4(s)
The net ionic equation is:
Pb2+(aq) + C2O4^2-(aq) → PbC2O4(s)
3. Magnesium chromate + Copper(II) sulfate
The balanced molecular equation is:
MgCrO4 + CuSO4 → MgSO4 + CuCrO4
To write the ionic equation, we break apart the soluble ionic compounds into their respective ions:
MgCrO4(aq) + CuSO4(aq) → MgSO4(aq) + CuCrO4(s)
Next, we separate the strong electrolytes into ions:
Mg^2+(aq) + CrO4^2-(aq) + Cu^2+(aq) + SO4^2-(aq) → Mg^2+(aq) + SO4^2-(aq) + CuCrO4(s)
Finally, we cancel out the spectator ions:
CrO4^2-(aq) + Cu^2+(aq) → CuCrO4(s)
The net ionic equation is:
CrO4^2-(aq) + Cu^2+(aq) → CuCrO4(s)
In summary:
1. Arsenic(III) iodide + Sodium sulfide:
Net ionic equation: As3+(aq) + 3I^-(aq) + 3S^2-(aq) → As2S3(s)
2. Lead(II) nitrate + Ammonium oxalate:
Net ionic equation: Pb2+(aq) + C2O4^2-(aq) → PbC2O4(s)
3. Magnesium chromate + Copper(II) sulfate:
Net ionic equation: CrO4^2-(aq) + Cu^2+(aq) → CuCrO4(s)