College Chemistry

If 3.00 moles of NaCl were mixed with 0.9 L of 0.5 M of AgNO3, how many moles of solid would form? Include the formula for the solid.

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  1. I worked this earlier today but with different numbers.
    3.00 mols NaCl
    mols AgNO3 = M x L = 0.9L x 0.5M = 0.45
    .........AgNO3 + NaCl ==> AgCl
    I.......0.45.....................
    add.............3.00............
    C.......-0.45..-0.45......+0.45
    E.........0.....2.55.......0.45
    You can see from the equilibrium line that 0.45 mols AgCl will form, all of the AgNO3 will react, and you will have 2.55 mols NaCl left unreacted.

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