# math

an unbiased coin is tossed six times. find the probability of the given event - the coin lands heads more than once.

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prob(no heads) = (1/2)^6 = 1/64
prob(1 head) = C(6,1) (1/2)^1 (1/2)^5 = 6/64

prob (more than 1 head) = 1 - 1/64 - 6/64
= 57/64

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2. thank you so much, this helped alot

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