math

an unbiased coin is tossed six times. find the probability of the given event - the coin lands heads more than once.

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  1. must exclude no heads and 1 head
    prob(no heads) = (1/2)^6 = 1/64
    prob(1 head) = C(6,1) (1/2)^1 (1/2)^5 = 6/64

    prob (more than 1 head) = 1 - 1/64 - 6/64
    = 57/64

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  2. thank you so much, this helped alot

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