calculate the concentration of a solution when 35.0g of k2so4 is dissolved in enough water to make to make 125.0g solution.

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What kind of concentration. Since you've listed grams solution instead of L of solution, you need the density or grams solvent.
In any case you need mols K2SO4 and that is grams/molar mass.

13. A student mixes 100.0 mL of 0.500 M AgNO3 with 100.0 mL of 0.500 M CaCl2. (8 points)

a. Write the balanced molecular equation for the reaction.
b. Write the net I onic equation for the reaction.
c. How many grams of precipitate will form?
d. What is the concentration of Ag+, NO3‒, Ca2+, and Cl‒ in the final solution (assume volumes are additive

To calculate the concentration of a solution, we need to divide the amount of solute (in this case, K2SO4) by the total volume of the solution.

Step 1: Calculate the total volume of the solution
Since the problem states that 35.0g of K2SO4 is dissolved in enough water to make a 125.0g solution, we can assume that the total mass of the solvent (water) is 125.0g - 35.0g = 90.0g.

Step 2: Convert the mass of water to volume
To convert the mass of water to volume, we need to know the density of water, which is approximately 1 g/mL at room temperature. Therefore, the volume of water in mL is equal to the mass of water in grams.

Step 3: Calculate the concentration
The concentration is the amount of solute (K2SO4) per unit volume (mL) of the solution. To calculate it, we divide the mass of K2SO4 by the volume of the solution (water).

Now, let's put all the steps together to calculate the concentration:

Step 1: Calculate the total volume of the solution
Total mass of the solution = 125.0g
Mass of K2SO4 = 35.0g
Mass of water = Total mass of the solution - Mass of K2SO4 = 125.0g - 35.0g = 90.0g

Step 2: Convert the mass of water to volume
Volume of water = Mass of water = 90.0 mL

Step 3: Calculate the concentration
Concentration = Mass of K2SO4 / Volume of solution
Concentration = 35.0g / 90.0 mL = 0.3889 g/mL

Therefore, the concentration of the K2SO4 solution is approximately 0.3889 g/mL.