The probability of choosing a 6 at random from a standard deck of playing cars is 1/13.Use this information for 1 and 3.
1. what is the complement of the event of choosing a 6 ?
2. What is the probability of the complement of the event of choosing a 6 ?
3. You roll a standard number cube 1,000 times. Predict the number of times you will roll a 2 or a 5.
1.
What is 1 - 1/13 ?
2. .......
3.
to get a 2 ---> 11
to get a 5 ---> 14, 41, 23, 32 or 4 ways
so to get a 2 or 5 ----> 5 possible outcomes
prob(2 or 5) = 5/36
so in 1000 tosses we expect
(5/36)(1000) or appr 139 times
I don't know what is the question between 1 and 2 , the question 2 has probability (what is that mean)
1. did you mean 1 - 1/13= 12/13
1. The complement of an event refers to all the outcomes that are not part of the event. In this case, since we want to find the complement of choosing a 6, it means we want to find all the outcomes that are not a 6. In a standard deck of playing cards, there are 4 different suits (hearts, diamonds, clubs, spades) and each suit contains 13 cards. Since there are 4 sixes in the deck, there are a total of 52 - 4 = 48 cards that are not a 6. Therefore, the complement of the event of choosing a 6 is choosing any card that is not a 6.
2. To find the probability of the complement, we need to divide the number of favorable outcomes (cards that are not a 6) by the total number of possible outcomes (all the cards in the deck). In this case, the number of favorable outcomes is 48 (cards that are not a 6) and the total number of possible outcomes is 52 (all the cards in the deck). Therefore, the probability of the complement of choosing a 6 is 48/52, which simplifies to 12/13.
3. Assuming the standard number cube is a fair cube with equally likely outcomes, it has 6 faces numbered from 1 to 6. The probability of rolling a 2 or a 5 on a fair number cube is 2/6, since there are 2 favorable outcomes (rolling a 2 or a 5) out of the 6 possible outcomes.
To predict the number of times you will roll a 2 or a 5 in 1,000 rolls, you can multiply the probability of rolling a 2 or a 5 (2/6) by the number of rolls (1,000).
Predicted occurrences = Probability of event * Number of trials
Predicted occurrences = (2/6) * 1000
Predicted occurrences = (1/3) * 1000
Predicted occurrences = 333.33 (rounded to the nearest whole number)
Therefore, we can predict that you will roll a 2 or a 5 approximately 333 times when rolling a standard number cube 1,000 times.