Find the median, the first quartile,
the third quartile, the minimum, the maximum, and the rangeof the data;
34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58
median=46
median is the number in the "middle", for yours it is 46
first quartile : 34,36,38
third quartile : 46,48,50
minimum : What is the smallest number you see?
Maximum : What is the largest number you see?
range : The gap between the smallest and the largest (58-34)
Can someone answer the question because I don't understand how to get the answers.
To find the median, first sort the data in ascending order:
34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58
Since there are 13 numbers in the dataset, the median will be the value in the middle. In this case, the median is the sixth value, which is 44.
To find the first quartile, divide the dataset into four equal parts. Since there are 13 numbers, the first quartile will be the median of the lower half of the data. In this case, the lower half of the data is:
34, 36, 38, 40, 42, 44
The first quartile will be the median of this subset. Since there are six numbers, the first quartile will be the third value, which is 38.
To find the third quartile, you can follow a similar process. The upper half of the data is:
46, 48, 50, 52, 54, 56, 58
The third quartile will be the median of this subset. Since there are seven numbers, the third quartile will be the fourth value, which is 52.
The minimum value in the dataset is 34, and the maximum value is 58.
To find the range, subtract the minimum value from the maximum value. In this case, the range is 58 - 34 = 24.
Therefore, the statistics of the given dataset are:
Median: 44
First quartile: 38
Third quartile: 52
Minimum: 34
Maximum: 58
Range: 24