How many grams of acetic anhydride are needed to react with 3.82g of salicylic acid?
It's one mole to one mol; therefore, how many mols do you have in 3.82 g SA? That's mols SA = 3.82g/molar mass SA.
Then mols AA = mols SA
and g AA = mols AA x molar mass AA
To determine the number of grams of acetic anhydride needed to react with 3.82g of salicylic acid, we need to use the balanced chemical equation for the reaction between salicylic acid and acetic anhydride. The reaction is as follows:
C7H6O3 (salicylic acid) + (CH3CO)2O (acetic anhydride) → C9H8O4 (aspirin) + CH3COOH (acetic acid)
From the balanced equation, we can see that the molar ratio between salicylic acid and acetic anhydride is 1:1. This means that stoichiometrically, for every 1 mole of salicylic acid, we need 1 mole of acetic anhydride.
To calculate the grams of acetic anhydride needed, we can use the molar mass of salicylic acid to convert grams to moles, and then use the mole ratio to convert moles of salicylic acid to moles of acetic anhydride, and finally convert moles of acetic anhydride to grams.
1. Calculate moles of salicylic acid:
Moles of salicylic acid = mass of salicylic acid / molar mass of salicylic acid
Moles of salicylic acid = 3.82g / 138.12 g/mol (molar mass of salicylic acid)
2. Use the mole ratio:
Moles of acetic anhydride = Moles of salicylic acid (According to the mole ratio of 1:1)
3. Convert moles of acetic anhydride to grams:
Grams of acetic anhydride = Moles of acetic anhydride x molar mass of acetic anhydride
To get the final answer, simply substitute the values obtained from the calculations above into the equation and calculate.
However, note that we will require the molar mass of acetic anhydride to complete the calculation. Please provide the molar mass of acetic anhydride or let me know if you have any further questions.
To determine the number of grams of acetic anhydride needed to react with 3.82g of salicylic acid, we need to calculate the molar ratio between acetic anhydride and salicylic acid.
The balanced chemical equation for the reaction between acetic anhydride (C4H6O3) and salicylic acid (C7H6O3) is:
C4H6O3 + C7H6O3 → C9H8O4 + CH3COOH
From the balanced equation, we can see that the molar ratio between acetic anhydride and salicylic acid is 1:1.
1 mole of any substance is equal to its molar mass in grams. The molar mass of acetic anhydride (C4H6O3) is approximately 102.09 g/mol.
To find the number of moles of acetic anhydride needed, we can use the following equation:
moles = mass / molar mass
moles of acetic anhydride = 3.82g / 102.09 g/mol ≈ 0.0375 mol
Since the molar ratio between acetic anhydride and salicylic acid is 1:1, the number of moles of acetic anhydride needed is also 0.0375 mol.
To convert moles back to grams, we can use the molar mass of acetic anhydride:
grams = moles × molar mass
grams of acetic anhydride = 0.0375 mol × 102.09 g/mol ≈ 3.811g
Therefore, approximately 3.81 grams of acetic anhydride are needed to react with 3.82 grams of salicylic acid.