Can someone may sure that I balanced the following groups of equations correctly.
Write an equation to show how acetic acid reacts with water to produce ions in solution.
C2H4O2 + H2O >>>>>>> H3O + C2H3O
Write an equation for the neutralization of HCl and NaOH.
HCl + NaOH >>>>>> NaCl + H2O
Write the equation representing the decomposition of CaCO3.
CaCO3 >>>>>>> Ca+ CO
Complete and balance the following equations and name the product formed.
I am sure that I have them balanced correctly. Could you let me know if I have the correct product?
K2O(s)+H2O(l) >>2KOH = potassium hydroxide.
SrO(s) +H2O(l) >> Sr(OH)2 = strontium hydroxide.
SO3(s) + H2O(l) >>H2SO4 = sulfuric acid.
N2O5(s) + H20(l) >>>2HNO3 = hydrogen nitrate.
Write an equation to show how acetic acid reacts with water to produce ions in solution.
C2H4O2 + H2O >>>>>>> H3O + C2H3O
You need to show the charges on the ions; i.e., H3O^+ + C2H3O^-
Write an equation for the neutralization of HCl and NaOH.
HCl + NaOH >>>>>> NaCl + H2O
OK
Write the equation representing the decomposition of CaCO3.
CaCO3 >>>>>>> Ca+ CO
CaCO3 ==> CaO + CO2
Complete and balance the following equations and name the product formed.
I am sure that I have them balanced correctly. Could you let me know if I have the correct product?
K2O(s)+H2O(l) >>2KOH = potassium hydroxide.
OK
SrO(s) +H2O(l) >> Sr(OH)2 = strontium hydroxide.
OK
SO3(s) + H2O(l) >>H2SO4 = sulfuric acid.
OK
N2O5(s) + H20(l) >>>2HNO3 = hydrogen nitrate.
The common name is nitric acid
The first two equations you provided are balanced correctly:
1. Acetic acid reacting with water:
C2H4O2 + H2O → H3O+ + C2H3O2-
2. Neutralization of HCl and NaOH:
HCl + NaOH → NaCl + H2O
However, the equation for the decomposition of CaCO3 needs to be balanced:
CaCO3 → CaO + CO2
And the last equation also needs balancing:
N2O5 + H2O → 2HNO3
The correct products you provided are:
1. K2O(s) + H2O(l) → 2KOH (Potassium hydroxide)
2. SrO(s) + H2O(l) → Sr(OH)2 (Strontium hydroxide)
3. SO3(s) + H2O(l) → H2SO4 (Sulfuric acid)
4. N2O5(s) + H2O(l) → 2HNO3 (Nitric acid)
To check if the given equations are balanced correctly and if the products are named correctly, let's go through each equation step by step:
1. Equation for the reaction of acetic acid with water:
C2H4O2 + H2O → H3O+ + C2H3O-
To balance the equation, you need to make sure that there are an equal number of atoms on both sides of the equation. In this case, everything seems to be balanced correctly.
2. Equation for the neutralization of HCl and NaOH:
HCl + NaOH → NaCl + H2O
Again, this equation seems to be balanced correctly with an equal number of atoms on both sides. The product is named correctly as sodium chloride and water.
3. Equation for the decomposition of CaCO3:
CaCO3 → CaO + CO2
This equation represents the decomposition of calcium carbonate into calcium oxide (CaO) and carbon dioxide (CO2). From the equation, it seems balanced correctly, and the product is named correctly.
Now, moving on to the equations that you completed:
4. Equation for K2O + H2O:
K2O + H2O → 2KOH
The equation is balanced correctly, and the product is named correctly as potassium hydroxide.
5. Equation for SrO + H2O:
SrO + H2O → Sr(OH)2
Again, the equation is balanced correctly, and the product is named correctly as strontium hydroxide.
6. Equation for SO3 + H2O:
SO3 + H2O → H2SO4
The equation is balanced correctly, and the product is named correctly as sulfuric acid.
7. Equation for N2O5 + H2O:
N2O5 + H2O → 2HNO3
Once again, the equation is balanced correctly, and the product is named correctly as nitric acid.
Based on the explanations above, it seems that you have balanced the equations correctly and named the products accurately. Well done!