using a constant rate, you can saw a log into 3 pieces in 12 minutes. At the sam constant rate, how long will it take you to cut a siliar log (if the same size) into 6 pieces?
would you do a rate formula or what?
I'm really stuck on this one!
If it takes you 4 minutes to make one slice (12/3 = 4), then it should take 4 times 6 to saw a similar log into 6 pieces.
4 * 6 = 24
Arrg, stop deleting my message, my last one was correct.
first of all, cutting 2 slices of a log will make it into 3. if it took 12 minutes to cut 2 slices into 3, it takes 6 minuts to cut a slice.
Now taking the same log, you need 6 pieces. so cutting 3 more times in addition to the first two would mean 30 mins.
2 slices = 3 pieces
from 3 logs, 3 slice = 6 pieces
5 slice x 6 minutes each = 30 mins
I goofed! You're right, Chris. :-)
2 cuts = 3 pieces
1 cut = 6 minutes.
5 cuts = 6 pieces
5 cuts = 30 minutes.
Right on Chris.
To solve this problem, we can use the concept of rates. Let's assume that the rate at which you cut the log is "x pieces per minute."
According to the given information, you can cut a log into 3 pieces in 12 minutes. This means that in 12 minutes, you can cut at a rate of 3 pieces. So, we can set up the equation:
x pieces/minute * 12 minutes = 3 pieces
Now, let's solve for the rate 'x':
x = 3 pieces / 12 minutes
x = 1/4 pieces per minute
Now that we know the rate at which you can cut the log, we can find the time it takes to cut a similar log into 6 pieces using the same rate.
Using the rate formula:
Rate = Output / Time
We know that the rate is 1/4 pieces per minute, and we want to find the time it takes to cut 6 pieces. So, we can rearrange the formula:
Time = Output / Rate
Time = 6 pieces / (1/4 pieces per minute)
Simplifying further:
Time = 6 pieces * (4 pieces / 1 minute)
Time = 24 minutes
Therefore, using the same rate, it will take you 24 minutes to cut a similar log into 6 pieces.