what is the mass percent of an aqueous sodium hydroxide solution in which the molarity of NaOH is 4.37M? the density of the solution is 1.1655 g/mL.
1.1655 g/mL x 1000 mL x %NaOH x 1/40 = 4.37M. Solve for %.
8.99
To find the mass percent of an aqueous sodium hydroxide (NaOH) solution, we need to calculate the mass of NaOH in a given volume of the solution and divide it by the mass of the entire solution, and then multiply by 100.
Let's start with calculating the mass of NaOH in 1 liter (1000 mL) of the solution. We know the molarity of NaOH is 4.37 M, which means there are 4.37 moles of NaOH in 1 liter of the solution.
The molecular weight of NaOH is calculated as follows:
Sodium (Na) = 23.0 g/mol
Oxygen (O) = 16.0 g/mol
Hydrogen (H) = 1.0 g/mol
So, the molecular weight of NaOH = 23.0 + 16.0 + 1.0 = 40.0 g/mol.
Therefore, in 1 liter (1000 mL) of solution, the mass of NaOH is:
Mass of NaOH = Molarity x Molecular weight = 4.37 mol/L x 40.0 g/mol = 174.8 g/L.
We can now calculate the mass of NaOH in the given volume of the solution (density = 1.1655 g/mL):
Mass of NaOH = Volume x Density = 1 mL x 1.1655 g/mL = 1.1655 g.
Now, to find the mass percent, we divide the mass of NaOH by the mass of the entire solution and multiply by 100:
Mass percent of NaOH = (Mass of NaOH / Mass of solution) x 100.
Since the mass of the entire solution is not provided, we cannot calculate the exact mass percent. However, you can provide the volume of the solution, and I can help you calculate the mass percent based on that.
To find the mass percent of a solute in a solution, you need to know the mass of the solute and the mass of the solution.
In this case, the solute is sodium hydroxide (NaOH), and the solution is an aqueous sodium hydroxide solution.
Given information:
- Molarity of NaOH = 4.37 M
- Density of the solution = 1.1655 g/mL
To solve this problem, follow these steps:
Step 1: Find the molecular weight of NaOH.
The molecular weight of NaOH is calculated by adding the atomic masses of sodium (Na), oxygen (O), and hydrogen (H).
Na: 22.99 g/mol
O: 16.00 g/mol
H: 1.01 g/mol
Molecular weight of NaOH = 22.99 + 16.00 + 1.01 = 40.00 g/mol
Step 2: Calculate the mass of NaOH in the solution using the molarity and volume.
Molarity (M) = Moles of solute / Volume of solution (in liters)
In this case, the volume is not directly given, but we can assume 1 liter for simplicity. So, 1 L = 1000 mL.
Molarity (M) = 4.37 M
Volume (V) = 1 L = 1000 mL
Using the formula, Moles of solute = Molarity × Volume
Moles of NaOH = 4.37 mol/L × 1 L = 4.37 mol
Now, since the molecular weight of NaOH is 40.00 g/mol, you can find the mass of NaOH:
Mass of NaOH = Moles × Molecular weight
Mass of NaOH = 4.37 mol × 40.00 g/mol = 174.8 g
Step 3: Calculate the mass of the solution.
To find the mass of the solution, you need to know the density. Density is defined as mass divided by volume.
Density (D) = Mass (m) / Volume (V)
Rearranging the formula, Mass (m) = Density × Volume
Density = 1.1655 g/mL
Volume (V) = 1 L = 1000 mL
Mass of solution = Density × Volume
Mass of solution = 1.1655 g/mL × 1000 mL = 1165.5 g
Step 4: Calculate the mass percent of NaOH.
Mass percent = (Mass of NaOH / Mass of solution) × 100
Mass percent = (174.8 g / 1165.5 g) × 100 ≈ 15.01%
Therefore, the mass percent of NaOH in the aqueous solution is approximately 15.01%.