robin is standing terrified at the end of a diving board, which is high above the water. if robin has a mass of 75 kg and is standing .6m from the board's pivot point, what torque is robin exerting on the board
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The torque exerted by Robin on the board is equal to her mass multiplied by the distance from the pivot point, multiplied by the acceleration due to gravity (9.8 m/s2).
Torque = 75 kg x 0.6 m x 9.8 m/s2
= 441 Nm
To find the torque that Robin is exerting on the diving board, we need to use the formula for torque:
Torque = Force × Distance
In this case, Robin's mass does not directly tell us the force he is exerting. However, we know that weight is the force exerted by the mass due to gravity. So, to calculate the force, we can use the equation:
Force = Mass × Acceleration due to gravity
The acceleration due to gravity on Earth is approximately 9.8 m/s^2.
Force = 75 kg × 9.8 m/s^2 = 735 N
Now, we can calculate the torque using the formula:
Torque = Force × Distance
Distance = 0.6 m
Torque = 735 N × 0.6 m = 441 N·m
Therefore, Robin is exerting a torque of 441 N·m on the diving board.
To calculate the torque exerted by Robin on the diving board, we will use the formula:
Torque = Force * Distance * sin(θ)
Here, the force is the weight of Robin, which can be calculated as the product of mass and acceleration due to gravity (9.8 m/s^2).
Force = mass * acceleration due to gravity
= 75 kg * 9.8 m/s^2
= 735 N
The distance mentioned in the problem is the distance from the pivot point to Robin, which is given as 0.6 m.
θ represents the angle between the distance and the force. Since Robin is standing vertically on the board, the angle is 90 degrees.
Now, we can calculate the torque:
Torque = Force * Distance * sin(θ)
= 735 N * 0.6 m * sin(90°)
= 735 N * 0.6 m * 1
= 441 Nm
Therefore, Robin is exerting a torque of 441 Newton meters on the diving board.