A glass window pane has an area of 3.50 m2 and a thickness of 0.600 cm. If the temperature difference between its surfaces is 23.0°C, what is the rate of energy transfer by conduction through the window?

34.1

To find the rate of energy transfer by conduction through the window, we can use the formula:

Q = (k * A * ΔT) / d

where:
Q is the rate of energy transfer (in joules per second or watts),
k is the thermal conductivity of the material (in watts per meter per degree Celsius),
A is the area of the window (in square meters),
ΔT is the temperature difference between the two surfaces (in degrees Celsius),
and d is the thickness of the window (in meters).

First, let's convert the thickness of the window from centimeters to meters:

d = 0.600 cm / 100 = 0.006 m

Now we can substitute the given values into the formula:

Q = (k * A * ΔT) / d

The thermal conductivity of glass can vary, but we'll assume a typical value of 0.8 W/(m·°C) for this calculation.

Q = (0.8 W/(m·°C) * 3.50 m^2 * 23.0°C) / 0.006 m

Calculating this expression will give us the rate of energy transfer by conduction through the window.