How fast does water flow from a hole at the bottom of a very wide, 7.9m deep storage tank filled with water? Ignore viscosity
speed of exiting water is :V = sqrt(2*g*H)
where g is gravity at 9.81 and H is height of water:
sqrt(2*9.81*7.9)=12.44m/s
To determine the speed at which water flows from a hole at the bottom of a storage tank, we can use Torricelli's law, which is derived from Bernoulli's equation. Torricelli's law states that the speed of water flowing out of a hole at the bottom of a container is equal to the square root of twice the acceleration due to gravity (9.8 m/s^2) multiplied by the height of the water column.
In this case, the height of the water column is 7.9 meters. So, the formula to calculate the speed can be written as:
v = √(2gh)
Where:
v = velocity of water flowing out of the hole
g = acceleration due to gravity (approximately 9.8 m/s^2)
h = height of the water column (7.9 meters)
Now, we can substitute the values into the formula:
v = √(2 * 9.8 * 7.9)
Calculating this equation, we find:
v ≈ √(154.84)
v ≈ 12.46 m/s
Therefore, the water will flow out of the hole at a speed of approximately 12.46 meters per second.