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Chemistry
Solutions
Molarity
What is the molarity of a solution of H3PO4 if 11.1 mL is neutralized by 33.2 mL of 0.161 M NaOH?
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A solution of 0.316 M KOH is used to neutralize 16.0 mL H3PO4 solution
H3PO4(aq) + 3KOH(aq) �¨ K3PO4(aq) + 3H2O(l) If 30.3 mL
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mols KOH = M x L = ? Using the coefficients in the balanced equation, convert mols KOH to mols
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A solution of 0.314M KOH is used to neutralize 10.0mL H3PO4 solution.
H3PO4(aq) + 3KOH(aq) → K3PO4(aq) + 3H2O(lIf 29.3mL KOH
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mols KOH = M x L = ? Using the coefficients in the balanced equation, convert mols KOH to mols
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A 5.00 mL sample of an aqueous solution of H3PO4 requires 43.2mL of 0.285M NaOH to convert all of the H3PO4 to Na2HPO4. The
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H3PO4 + NaOH ==> NaH2PO4 + H2O mols NaOH = M x L = ? 1 mol NaOH = 1 mol H3PO4 M H3PO4 = mols H3PO4/L
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A solution of 0.314M KOH is used to neutralize 10.0mL H3PO4 solution.
H3PO4(aq) + 3KOH(aq) → K3PO4(aq) + 3H2O(l) If 29.3mL KOH
Top answer:
See your post above.
Read more.
A solution of 0.314M KOH is used to neutralize 10.0mL H3PO4 solution.
H3PO4(aq) + 3KOH(aq) → K3PO4(aq) + 3H2O(l) If 29.3mL KOH
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Dude I dunno lmao
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What is the molarity of a NaOH solution if 21.3 mL of the NaOH solution is neutralized by 10.4 mL of 6.10 M H3PO4?
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3NaOH + H3PO4 ==> 3H2O + Na3PO4 mols H3PO4 = M x L = ? mols NaOH = 3*mols NaOH from the coefficients
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A 75.0g sample of liquid contains 17.5% by mass of H3PO4 (molar mass=98.0g/mol). If 215.0mL of Ba(OH)2 is needed to completely
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2H3PO4 + 3Ba(OH)2 ==> Ba3(PO4)2 + 6H2O mass H3PO4 in the sample = 75.0 x 0.175 = approx 13 but this
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Use the following balanced equation.
3Sr(OH)2 + 2H3PO4 --> 6H20 + Sr3(PO4)2 20 mL of H3PO4 is required to react with 40 mL of a
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See your other posts below.
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hello this is ellie again. I need help on this one problem A solution of 0.314M KOH is used to neutralize 10.0mL H3PO4 solution.
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See your post below.
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The molarity of H3PO4 is .01 M. The density of the H3PO4 in the solution is .0009 g/mL. What is the mass percent of H3PO4 in the
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0.01M means 0.01 mols H3PO4/1000 mL solution. The molar mass is 98; therefore, there are 0.98 grams
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