Math

Write an equation in slope intercept form of the line that is perpendicular to the given line and that passes through the given point

3x-4y=8 ; (-6,5)

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  1. y-5 = -4/3 (x+6)
    now just convert that to y = mx+b

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  2. When I did it I got y=3/4x+9 1/2... Did u get that also ?

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  3. y - 5 = -4/3 (x+6)
    y - 5 = -4/3 x - 8
    y = -4/3 x - 3

    the slope has to be -4/3, since the original line had slope 3/4 and you want a perpendicular line.

    Your line is parallel to it, not perpendicular.

    And, as long as you're doing algebra now, lose the mixed numbers. They're just a nuisance. 19/2 is much more useful in calculations than 9 1/2.

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