I have a few match problems that I can't figure out.

1.solve: 3x+5=x√7 (that's a radical sign)
2.factor: (2k+3)2-(2x+3)(y-2)-20(y-2)2 (the "2" after (2k+3) ans (y-2) is suppose to be a square sign.

thanks if you can help, or even if you can't

For number 2:
First, FOIL out (2k+3)^2. You should get:
4k^2 + 12k + 9.
Then, FOIL out (2x+3)(y-2). You should get:
2xy - 4x + 3y - 6. You wanted to subtract the first part by the second:
4k^2 + 12k + 9 -(2xy - 4x + 3y - 6).
Distribute the negative:
4k^2 + 12k + 9 - 2xy + 4x - 3y + 6.
Combine like-terms:
4k^2 + 12k - 2xy + 4x - 3y + 15.
Before multiplying 20 by (y-2)^2, FOIL out the (y-2)^2. You should get:
y^2 - 4y + 4.
Now multiply by 20:
20y^2 - 80y + 80.
Now, take the equation from 6 lines up and subtract by this part:
4k^2 + 12k - 2xy + 4x - 3y + 15 -(20y^2 - 80y + 80).
Distribute the negative:
4k^2 + 12k - 2xy + 4x - 3y + 15 - 20y^2 + 80y - 80.
Now, combine like-terms to finish:
4k^2 + 12k - 2xy + 4x + 77y - 20y^2 - 65.

To solve the equation 3x + 5 = x√7, we need to isolate x.

1. Start by subtracting x from both sides of the equation to get rid of x on the right side:
3x - x + 5 = x√7 - x
Simplified: 2x + 5 = x√7

2. Next, subtract 5 from both sides of the equation to isolate x:
2x + 5 - 5 = x√7 - 5
Simplified: 2x = x√7 - 5

3. To eliminate the square root on the right side, square both sides of the equation:
(2x)^2 = (x√7 - 5)^2
Simplified: 4x^2 = (x√7 - 5)(x√7 - 5)

4. Expand the right side of the equation using the foil method:
4x^2 = (x^2√7 - 5x√7 - 5x√7 + 25)
Simplified: 4x^2 = x^2√7 - 10x√7 + 25

5. Combine like terms on the right side of the equation:
4x^2 = x^2√7 - 20x√7 + 25

6. Move all terms to one side to set the equation equal to zero:
4x^2 - x^2√7 + 20x√7 - 25 = 0

Now you have a quadratic equation that can be solved using various methods like factoring, completing the square, or using the quadratic formula.