A ball is filled with helium. If the ball has a diameter of 24 inches, what is the maximum amount of helium that the ball may hold?
no maximum amount. That depends on the pressure. Helium may be added to the ball until its skin ruptures.
However, the volume of the ball is
4/3 pi * 12^3 in^3
I have no idea. It depends on the pressure in the ball and the temperature.
P V = n R T
so
n = moles of He = P V/ (RT) = P (4/3)r^3 /(RT)
a mol of He has mass of 4 grams
To find the maximum amount of helium that the ball can hold, we need to calculate the volume of the ball.
The formula for the volume of a sphere is:
V = (4/3) * π * r^3
Where V is the volume and r is the radius of the sphere.
In this case, we have the diameter of the ball, which is 24 inches. The radius can be found by dividing the diameter by 2.
So, r = 24 inches / 2 = 12 inches.
Now, we can substitute the value of the radius into the volume formula:
V = (4/3) * π * (12 inches)^3
Calculating this expression will give us the maximum amount of helium that the ball can hold.