Bioluminescence Some species of dinoflagellate (a type of unicellular plankton) can produce light as the result of biochemical reactions within the cell. This light is an example of bioluminescence. It is found that bioluminescence in dinoflagellates can be triggered by deformation of the cell surface with a pressure as low as one dyne (10^−5N) per square centimeter.
A. What is this pressure in pascals?
P=___Pa?
B. What is this pressure in atmospheres?
P=___atm?
A. .10
A. To convert the pressure from dyne per square centimeter to pascals, we can use the conversion factor: 1 dyne per square centimeter = 0.1 pascals.
Therefore, to determine the pressure in pascals, we need to multiply the given pressure in dyne per square centimeter by the conversion factor:
P (in pascals) = 10^(-5) N/cm^2 × 0.1 pascals/dyne = 10^(-6) pascals.
So the pressure is 10^(-6) pascals.
B. To convert the pressure from pascals to atmospheres, we need to use the conversion factor: 1 atmosphere = 101325 pascals.
Therefore, to determine the pressure in atmospheres, we need to divide the given pressure in pascals by the conversion factor:
P (in atmospheres) = (10^(-6) pascals) / (101325 pascals/1 atmosphere) ≈ 9.87 × 10^(-12) atmospheres.
So the pressure is approximately 9.87 × 10^(-12) atmospheres.
To answer these questions, we need to convert the given pressure from dyne per square centimeter to pascals and atmospheres. Here's how you can do it:
1. Converting pressure from dyne per square centimeter to pascals:
The unit conversion relationship we need is: 1 dyne per square centimeter (dyn/cm²) = 0.1 pascal (Pa).
To find the pressure in pascals, simply multiply the given pressure in dyne per square centimeter by the conversion factor:
P (Pa) = 1 dyne/cm² * 0.1 Pa/dyne/cm²
Therefore, P (Pa) = 0.1 Pa.
So, the pressure is 0.1 pascals.
2. Converting pressure from dyne per square centimeter to atmospheres:
The unit conversion relationship we need is: 1 atmosphere (atm) = 1.01325 × 10^6 pascals (Pa).
To find the pressure in atmospheres, divide the pressure in pascals by the conversion factor:
P (atm) = 0.1 Pa / (1.01325 × 10^6 Pa/atm)
Therefore, P (atm) = 9.869 × 10^(-8) atm.
So, the pressure is approximately 9.869 × 10^(-8) atmospheres.
To summarize the answers:
A. The pressure is 0.1 pascals (Pa).
B. The pressure is approximately 9.869 × 10^(-8) atmospheres (atm).