When given the equation 2Na+Cl2=2NaCl. How many liters of Cl2 will it take to react completely with 63.0 grams of Na?
mols Na = grams/molar mass
Using the coefficients in the balanced equation, convert mols Na to mols Cl2.
Now convert mols Cl2 to liters remembering that mols x 22.4L/mol = ?L
To determine the number of liters of Cl2 required to react completely with 63.0 grams of Na, we first need to convert the mass of Na to moles using the molar mass of Na.
Step 1: Convert grams of Na to moles
The molar mass of Na (sodium) is approximately 22.99 g/mol.
Moles of Na = Mass of Na / Molar mass of Na
Moles of Na = 63.0 g / 22.99 g/mol
Moles of Na = 2.739 mol (rounded to three decimal places)
Step 2: Use the balanced chemical equation to determine the stoichiometric ratio between Na and Cl2
From the balanced chemical equation: 2Na + Cl2 → 2NaCl
We can see that 2 moles of Na reacts with 1 mole of Cl2.
Step 3: Determine the moles of Cl2 required
Moles of Cl2 = (moles of Na) / (stoichiometric ratio between Na and Cl2)
Moles of Cl2 = 2.739 mol / 2
Moles of Cl2 = 1.3695 mol (rounded to four decimal places)
Step 4: Convert moles of Cl2 to volume in liters
To convert moles of Cl2 to liters, we need to use the ideal gas law at standard temperature and pressure (STP), where 1 mole of any gas occupies 22.4 liters.
Volume of Cl2 in liters = Moles of Cl2 × (22.4 liters/mol)
Volume of Cl2 in liters = 1.3695 mol × 22.4 liters/mol
Volume of Cl2 in liters = 30.66 liters (rounded to two decimal places)
Therefore, it will take approximately 30.66 liters of Cl2 to react completely with 63.0 grams of Na.