alg 2.

solve. we can use a calculator on this part...
2e^-x+4=21. how do i do this problem.

i know that you subtract 4, but what do you do after that?

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  1. 2e^-x+4=21
    2 e^-x = 17
    e^-x = 17/2
    1/e^x = 17/2
    so
    e^x = 2/17
    take natural log of both sides
    x = ln (2/17)

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  2. can you please show me how you got e^x=2/17. thanks

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  3. in general
    a^-b = 1/a^b

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