A shout down a well produces an echo in 2.00 seconds. How deep is the surface of the water in the well? Assume the speed of sound to be 343 m/s.
A shout down a well produces an echo in 2.00 seconds. How deep is the surface of the water in the well? Assume the speed of sound to be 343 m/s.
distance=time*speedsound
solve for distance. Then, well depth is one half distance.
so, in other words your saying 343*2.00 so we get 686, then half it?
to get 343 again.
To find the depth of the surface of the water in the well, we can use the formula:
d = (v * t) / 2
where:
d is the depth of the surface of the water in the well,
v is the speed of sound, and
t is the time it takes for the echo to return.
Given:
v = 343 m/s (speed of sound)
t = 2.00 seconds (time for the echo to return)
Plugging in the values into the formula, we get:
d = (343 m/s * 2.00 seconds) / 2
Simplifying:
d = 686 m / 2
d = 343 m
Therefore, the depth of the surface of the water in the well is 343 meters.
To determine the depth of the surface of the water in the well, we need to use the formula:
Depth = (Speed of Sound * Time) / 2
Given that the speed of sound is 343 m/s and the time for the echo is 2.00 seconds, we can substitute these values into the formula:
Depth = (343 m/s * 2.00 s) / 2
Now, let's calculate:
Depth = 686 m / 2
Depth = 343 m
Therefore, the surface of the water in the well is 343 meters deep.