# physics

A hammer with 10 J of kinetic energy hits a nail and pushes it 5.0 mm into a plank.
Both the hammer and nail come to rest after the collision.
What is the average force that acts on the nail while it moves the 5.0 mm?

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1. KE=mv²/2
v²= 2•KE/m
a= v²/2s
F=ma=mv²/2s= 2m•KE/2s m=
= KE/s=10/0.005 =2000 N

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posted by Elena
2. 74161

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posted by l,mpkml

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