Sue has a list of 8 CDs and 5 DVDs that she wants to buy. Her friends randomly select one item to give her. What is the probability Sue's friend will select a CD? a DVD?
CD = 8/13
DVE = 5/13
Thank you I was trying to over think that problem.
You're welcome.
To find the probability of selecting a CD, we need to determine the total number of options and the number of options that are CDs.
Step 1: Calculate the total number of options
Sue has a list of 8 CDs and 5 DVDs. Therefore, the total number of options is 8 + 5 = 13.
Step 2: Calculate the number of options that are CDs
Sue has 8 CDs, so the number of options that are CDs is 8.
Step 3: Calculate the probability of selecting a CD
To find the probability, divide the number of options that are CDs by the total number of options:
Probability of selecting a CD = (Number of CDs) / (Total number of options)
Probability of selecting a CD = 8 / 13 ≈ 0.615 (rounded to three decimal places)
So, the probability that Sue's friend will select a CD is approximately 0.615.
To find the probability of selecting a DVD, we can use the same steps.
Step 1: Calculate the total number of options (already done, 13)
Step 2: Calculate the number of options that are DVDs
Sue has 5 DVDs, so the number of options that are DVDs is 5.
Step 3: Calculate the probability of selecting a DVD
Probability of selecting a DVD = (Number of DVDs) / (Total number of options)
Probability of selecting a DVD = 5 / 13 ≈ 0.385 (rounded to three decimal places)
So, the probability that Sue's friend will select a DVD is approximately 0.385.