What mass of octane must be burned in order to liberate 5410 kJ of heat?

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  1. Do you have the heat of combustion? If not you can calculate it this way.
    2C8H18 + 25O2 ==> 16CO2 + 18H2O

    dHrxn = dH combustion = (n*dHo formation products) - n*dHo reactants).
    So you will obtain that many kJ for 228 g octane. Convert that to grams needed for 5410 kJ.
    Post your work if you get stuck.

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