For the system of linear equations below, use graphing to determine in which quadrant the solution lies.
x+2y=-2
-2x+y=14
Quadrant III
Quadrant I
Quadrant II
Quadrant IV
take a look here:
http://www.wolframalpha.com/input/?i=plot+x%2B2y%3D-2%2C+-2x%2By%3D14+%2C+x%3D0%2C+y%3D0
Is he right?
No he is not
To use graphing to determine the quadrant in which the solution lies, we need to plot the two equations on a coordinate plane:
The first equation is x + 2y = -2. To graph this equation, we can rewrite it as y = (-1/2)x - 1.
The second equation is -2x + y = 14. To graph this equation, we can rewrite it as y = 2x + 14.
Now, let's plot the two lines on a coordinate plane.
First line: y = (-1/2)x - 1
When x = 0, y = -1. So we plot the point (0, -1).
When y = 0, -1/2x = -1. This means x = 2. So we plot the point (2, 0).
Now we can draw the line passing through these two points.
Second line: y = 2x + 14
When x = 0, y = 14. So we plot the point (0, 14).
When y = 0, 2x = -14. This means x = -7. So we plot the point (-7, 0).
Now we can draw the line passing through these two points.
After graphing the two lines, we can see that they intersect in Quadrant III. Therefore, the solution to the system of linear equations lies in Quadrant III.
If this is for connections academy 9th grade math unit 7 lesson 3 then \/
Just refer back to this cheat sheet after completing a test, so you at least try to do your own work.
1. C
2. A
3. B
4. C
5. A
6. C
7. A
8. C
I can ensure you a 100% :)