Algebra

solve: Ln(x+2)-Ln(4x+3)=Ln(1/x)
I think this is a Log of Quotient

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  1. ln( x+2)/(4x+3) ) = ln (/x)

    (x+2)/(4x+3) = 1/x
    x^2 + 2x = 4x+3
    x^2 - 2x - 3 = 0
    (x-3)(x+1) = 0
    x = 3 or x = -1

    but if x = -1 , ln(4x+3) is undefined, so

    x = 3

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