An object-–spring system undergoes simple harmonic motion. If the mass of the object is doubled, what will happen to the period of the motion?

To determine what will happen to the period of the motion when the mass of the object is doubled in a simple harmonic motion system, we need to understand the relationship between the period and the mass.

In a simple harmonic motion, the period is the time it takes for one complete cycle of motion. It is represented by the symbol T. The period of a mass-spring system can be calculated using the formula:

T = 2π√(m/k)

Where:
T is the period,
m is the mass of the object,
k is the spring constant.

From this formula, we can observe that the period is inversely proportional to the square root of the mass of the object. In other words, as the mass increases, the period of the motion will increase.

So, when the mass of the object is doubled, the period of the motion will also increase.