You have been asked to do a dilution of a copper sulfate solution. The solution to be diluted is 2.88 M copper sulfate.
What volume of the 2.88 M copper sulfate is required to make 250 mL of 1.03 M copper sulfate solution?
To determine the volume of the 2.88 M copper sulfate solution required to make a 250 mL of 1.03 M copper sulfate solution, we can use the dilution formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
In this case:
C1 = 2.88 M
V1 = unknown
C2 = 1.03 M
V2 = 250 mL
Plugging the given values into the formula, we can solve for V1:
(2.88 M) V1 = (1.03 M) (250 mL)
Now, let's solve for V1:
V1 = (1.03 M) (250 mL) / (2.88 M)
V1 = 268.40 mL
Therefore, approximately 268.40 mL of the 2.88 M copper sulfate solution is required to make 250 mL of 1.03 M copper sulfate solution.
To calculate the volume of the 2.88 M copper sulfate solution required to make a 250 mL solution with a concentration of 1.03 M, we can use the dilution formula:
C1V1 = C2V2
Where:
C1 = concentration of the initial solution
V1 = volume of the initial solution
C2 = concentration of the final solution
V2 = volume of the final solution
In this case, the initial solution has a concentration of 2.88 M and the final solution should have a concentration of 1.03 M. The final volume is given as 250 mL.
Let's plug in the values into the formula and solve for V1, which represents the volume of the 2.88 M copper sulfate solution required:
(2.88 M) * V1 = (1.03 M) * (250 mL)
V1 = (1.03 M * 250 mL) / 2.88 M
V1 ≈ 89.93 mL
Therefore, approximately 89.93 mL of the 2.88 M copper sulfate solution is required to make 250 mL of 1.03 M copper sulfate solution.
you want to dilute it 2.88/1.03 =2.796times, which means 1 part original, 1.796 parts water.
what is 1 part? 1 Part= 250ml/2.796=89.4 ml original solution, then 250-89.4 ml water. Stir, label.